You are given a chessboard of size N x N, where the top left square is black. Each square contains a value. Find the sum of the values of all black squares and all white squares.
Remember that in a chessboard black and white squares are alternate. Input The first line of input will be the N size of the matrix. Then next N lines will consist of elements of the matrix. Each row will contain N elements since it is a square matrix.
Constraints:- 1 ≤ N ≤ 800 1 ≤ Matrix[i][j] ≤ 100000 Output Print two lines, the first line containing the sum of black squares and the second line containing the sum of white squares.
Explanation 1 The black square contains 1, 3, 5, 7, 9; sum = 25 The white square contains 2, 4, 6, 8; sum = 20
link:
import java.io.*; // for handling input/output
import java.util.*; // contains Collections framework
// don't change the name of this class
// you can add inner classes if needed
class Main {
public static void main (String[] args)throws IOException {
// Your code here
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
int n = Integer.parseInt(br.readLine());
int arr[][] = new int[n][n];
for(int i=0;i<n;i++){
String []input = br.readLine().split(" ");
for(int j=0;j<n;j++){
arr[i][j] = Integer.parseInt(input[j]);
}
}
matSum(arr,n);
}
static void matSum(int arr[][], int n){
long sum = 0,sum1 = 0;
for(int i=0;i<n;i++){
for(int j=0;j<n;j++){
if((i+j)%2==0){
sum += arr[i][j];
}else{
sum1 += arr[i][j];
}
}
}
System.out.println(sum);
System.out.println(sum1);
}
}
//method 02
```java
import java.io.*; // for handling input/output
import java.util.*; // contains Collections framework
// don't change the name of this class
// you can add inner classes if needed
class Main {
public static void main (String[] args) {
// Your code here
Scanner in = new Scanner(System.in);
int n = in.nextInt();
int arr[][] = new int [n][n];
for(int i=0; i<n; i++){
for(int j=0; j<n; j++){
arr[i][j] = in.nextInt();
}
}
int blackSum = 0;
int whiteSum = 0;
for(int i=0; i<n; i++){
for(int j=0; j<n; j++){
if((i+j)%2 ==0){
blackSum += arr[i][j];
}else{
whiteSum += arr[i][j];
}
}
}
System.out.println(blackSum);
System.out.println(whiteSum);
}
}
```