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Orange or Chocolate Candy? (Contest)

Orange or Chocolate Candy? (Contest) medium Time Limit: 2 sec Memory Limit: 128000 kB

PreviousOptimal Goodies (Contest)NextPacking Rectangles (Contest)

Last updated 2 years ago

Problem Statement :

Pino is super fond of candies. Today she has A chocolate candies, B orange candies, and C unknown candies. You are also given the happiness she gets after eating a particular candy. She wants to have exactly X chocolate candies and Y orange candies. She can transform an unknown candy into a candy of any type (chocolate or orange). Find the maximum happiness she can attain. Input The first line of input contains 5 integers X, Y, A, B, and C. The second line contains an A integer corresponding to the happiness of the various chocolate candies. The third line contains B integers corresponding to the happiness of the various orange candies. The fourth line contains C integers corresponding to the happiness of the various unknown candies.

Constraints:- 1 <= A, B, C <= 100000 1 <= X <= A 1 <= Y <= B 1 <= happiness of any candy <= 1000000000 (10^9) Output Output a single integer, the maximum happiness Pino can achieve by eating the candies. Example Sample Input 1:- 1 2 2 2 1 2 4 5 1 3

Sample Output 1:- 12

Sample Input 2:- 2 2 2 2 2 8 6 9 1 2 1

Sample Output 2:- 25

Explanation:- Pino eats the 2nd chocolate candy (happiness=4), then eats the 1st orange candy (happiness=4+5=9), then transforms the first unknown candy to orange candy and eats it (happiness=9+3=12)

link:

```java
import java.io.*; // for handling input/output
import java.util.*; // contains Collections framework

// don't change the name of this class
// you can add inner classes if needed
class Main {
    public static void main (String[] args) {
        // Your code here
        Scanner sc = new Scanner(System.in);
        int X = sc.nextInt();
        int Y = sc.nextInt();
        int A= sc.nextInt();
        int B = sc.nextInt();
        int C = sc.nextInt();
        int[] chocolate = new int[A];
        int[] orange = new int[B];
        int[] unknown = new int[C];
        int[] test = new int[X+Y];

        for(int i=0;i<A;i++)
        {
            chocolate[i]= sc.nextInt();
        } 
        for(int i=0;i<B;i++)
        {
            orange[i] = sc.nextInt();

        }
        for(int i=0;i<C;i++)
        {
            unknown[i]=sc.nextInt();
        }

        Arrays.sort(chocolate);
        Arrays.sort(orange);
        Arrays.sort(unknown);
        Arrays.sort(test);
        int ptr=0;


        for(ptr =0;ptr<X;ptr++)
        {
            test[ptr] = chocolate[A-1-ptr];
        }
        int ptr1=0;
        for(int i=ptr;i<ptr+Y;i++)
        {
            test[i] = orange[B-1-ptr1];
            ptr1++;
        }
        Arrays.sort(test);
        long sum=0l;
        int ptr2 = unknown.length-1;
        int ptr3 = test.length-1;
        for(int i=0;i<(X+Y);i++)
        {
            if(test[ptr3] > unknown[ptr2])
            {
                sum+=test[ptr3];
                ptr3--;
            }
            else{
                sum+=unknown[ptr2];
                ptr2--;
            }
        }
        System.out.println(sum);

    }
}
```
✅
https://my.newtonschool.co/playground/code/49vfxtbso6kh