115. Distinct Subsequences
Distinct Subsequences
Solution
public class Solution {
public int numDistinct(String s, String t) {
int m = s.length();
int n = t.length();
int[][] dp = new int[m + 1][n + 1];
for(int i = 0; i <= m; i ++ ){
dp[i][0] = 1;
}
for (int i = 1; i <= m; i++) {
for (int j = 1; j <= n; j++) {
if (s.charAt(i - 1) == t.charAt(j - 1)) {
dp[i][j] = dp[i - 1][j - 1] + dp[i-1][j];
} else {
dp[i][j] = dp[i-1][j];
}
}
}
return dp[m][n];
}
}Last updated