Given a nested list of integers, return the sum of all integers in the list weighted by their depth.
Each element is either an integer, or a list -- whose elements may also be integers or other lists.
Example 1: Given the list [[1,1],2,[1,1]], return 10. (four 1's at depth 2, one 2 at depth 1)
Example 2: Given the list [1,[4,[6]]], return 27. (one 1 at depth 1, one 4 at depth 2, and one 6 at depth 3; 1 + 42 + 63 = 27)
Solution
/** * // This is the interface that allows for creating nested lists. * // You should not implement it, or speculate about its implementation * public interface NestedInteger { * * // @return true if this NestedInteger holds a single integer, rather than a nested list. * public boolean isInteger(); * * // @return the single integer that this NestedInteger holds, if it holds a single integer * // Return null if this NestedInteger holds a nested list * public Integer getInteger(); * * // @return the nested list that this NestedInteger holds, if it holds a nested list * // Return null if this NestedInteger holds a single integer * public List<NestedInteger> getList(); * } */publicclassSolution {publicintdepthSum(List<NestedInteger> nestedList) {int[] sum =newint[1];for(NestedInteger nestedInteger: nestedList) {helper(nestedInteger, sum,1); }return sum[0]; }privatevoidhelper(NestedInteger nestedInteger,int[] sum,int level) {if (nestedInteger.isInteger()) { sum[0] +=nestedInteger.getInteger() * level; } else {List<NestedInteger> list =nestedInteger.getList();for(NestedInteger nestedInteger1 : list) {helper(nestedInteger1, sum, level+1); } } }}