Implement the following operations of a stack using queues.
push(x) -- Push element x onto stack.
pop() -- Removes the element on top of the stack.
top() -- Get the top element.
empty() -- Return whether the stack is empty.
Notes:
You must use only standard operations of a queue -- which means only push to back, peek/pop from front, size, and is empty operations are valid. Depending on your language, queue may not be supported natively. You may simulate a queue by using a list or deque (double-ended queue), as long as you use only standard operations of a queue. You may assume that all operations are valid (for example, no pop or top operations will be called on an empty stack).
Credits:Special thanks to @jianchao.li.fighter for adding this problem and all test cases.
Solution
classMyStack {privateQueue<Integer> q1;privateQueue<Integer> q2;publicMyStack() { q1 =newLinkedList<>(); q2 =newLinkedList<>(); }// Push element x onto stack.publicvoidpush(int x) {if (empty()) {q1.add(x); } elseif (q1.isEmpty()) {q2.add(x); } elseif (q2.isEmpty()) {q1.add(x); } }// Removes the element on top of the stack.publicvoidpop() {if (!empty()) {if (q1.isEmpty()) {while (q2.size() !=1) {q1.add(q2.poll()); }q2.poll();return; }if (q2.isEmpty()) {while (q1.size() !=1) {q2.add(q1.poll()); }q1.poll();return; } } }// Get the top element.publicinttop() {if (!empty()) {if (q1.isEmpty()) {while (q2.size() !=1) {q1.add(q2.poll()); }int temp =q2.peek();q1.add(temp);q2.poll();return temp; }if (q2.isEmpty()) {while (q1.size() !=1) {q2.add(q1.poll()); }int temp =q1.peek();q2.add(temp);q1.poll();return temp; } }return-1; }// Return whether the stack is empty.publicbooleanempty() {returnq1.isEmpty() &&q2.isEmpty(); }}