Given a binary tree containing digits from 0-9 only, each root-to-leaf path could represent a number. An example is the root-to-leaf path 1->2->3 which represents the number 123.
Find the total sum of all root-to-leaf numbers.
For example,
1
/ \ 2 3
The root-to-leaf path 1->2 represents the number 12. The root-to-leaf path 1->3 represents the number 13.
Return the sum = 12 + 13 = 25.
Solution
/** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */publicclassSolution {publicintsumNumbers(TreeNode root) {if(root ==null) return0;int[] value =newint[1];sumNumbers(root, value,newArrayList<>());return value[0]; }publicvoidsumNumbers(TreeNode root,int[] value,List<Integer> current) { ;current.add(root.val);if (root.left==null&&root.right==null) { value[0] +=convert(current); } else {if (root.left!=null) {sumNumbers(root.left, value, current); }if (root.right!=null) {sumNumbers(root.right, value, current); } }if (!current.isEmpty())current.remove(current.size() -1); }publicintconvert(List<Integer> list) {int sum =0;int temp =1;for (int i =list.size() -1; i >=0; i--) { sum += temp *list.get(i); temp *=10; }return sum; }}