You are climbing a stair case. It takes n steps to reach to the top.
Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top?
Note: Given n will be a positive integer.
public class Solution {
public int climbStairs(int n) {
if (n == 1) return 1;
if (n == 2) return 2;
int[] results = new int[n + 1];
results[1] = 1;
results[2] = 2;
for (int i = 3; i <= n; i++) {
results[i] = results[i - 1] + results[i - 2];
}
return results[n];
}
}
//method 2
public class Solution {
public int climbStairs(int n) {
if (n == 1) return 1;
if (n == 2) return 2;
int first=1;
int second=2;
int third=0;
for (int i = 3; i <= n; i++) {
third = first + second;
first=second;
second=third;
}
return third;
}
}
// recursion
public class Solution {
public int climbStairs(int n) {
if(n==0){
return 1;
}
if(n<0){
return 0;
}
int path1=climbStairs(n-1);
int path2=climbStairs(n-2);
return path1+path2;
}
}